the perimeters of two similar triangles are 25cm and 15cm.if one side of the first triangle is 9cm, find the corresponding side of the second triangle
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We are given that
AB= 9, per(∆ABC)=25, per(∆DEF)=15
Make a ∆ABC and ∆DEF
Such that AB is corresponding DE
PER(∆ABC)/PER(∆DEF)=AB/DE+BC/EF+AC/DF _this is the property
Now, per(∆ABC)/per(∆DEF)=AB/DE
We get 25/15=9/DE
25DE=9×15
DE=135/25
=5.4(ANS
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