Question

The perimeters of two similar triangles are 30 cm and 20 cm
respectively. If one side of one triangle is 12 cm, then find the length
of corresponding side of other triangle.​

Answer 1

Answer:

$perimeter \ \: of \: triangle \: 1 \div perimeter \: of \: triangle \: 2 \: = \: \frac{12}{x}$

$\frac{30}{20} = \frac{12}{x}$

$x = \frac{12 \times 20}{30}$

$x = 8cm$