The perimeters of two similar triangles are 30 cm and 20 cm respectively.
If one side of the first triangle is 9 cm long, find the length of the
corresponding side of the second triangle.
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The side of the other triangle corresponding to 12 cm side of the first one will be 12 * 20/30 = 8 cm, since sides and perimeter are linear and also similarity is a linear relation. Triangle ABC has AB = 10, BC = 24, and AC = 26. The perpendicular bisector of AC intersects the extension of AB at O.
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