The perimeters of two similar triangles are 32 cm and 28 cm respectively. If the median of one triangle is 12
find the corresponding median of the other triangle
Answers
Answer:
Length of AB is 16 cm
Step-by-step explanation:
Theorem : The ratio of the perimeter of two similar triangle is equal to the ratio of their respective sides .
Perimeter of triangle ABC = 32 cm
Perimeter of triangle PQR = 24 cm
Length of PQ = 12 cm
So, Using Theorem :
\frac{\text{Perimeter of triangle ABC}}{\text{Perimeter of triangle PQR}}=\frac{AB}{PQ}
Perimeter of triangle PQR
Perimeter of triangle ABC
=
PQ
AB
\frac{32}{24}=\frac{AB}{12}
24
32
=
12
AB
\frac{32 \times 12}{24} = AB
24
32×12
=AB
16 = AB16=AB
Hence Length of AB is 16 cm
Given : The perimeters of two similar triangles are 32 cm and 28 cm respectively. If the median of one triangle is 12
To find : the corresponding median of the other triangle
Solation:
In two similar triangles Corresponding sides are in proportion.
Ratio of corresponding sides = Ratio of corresponding Median
Ratio of corresponding sides = Ratio of Perimeter
From Both
Ratio of corresponding Median = Ratio of Perimeter
Let sat corresponding median of other triangle is x cm
=> 12/x = 32/28
=> x = 12 * 28 /32
=> x = 12 * 7 / 8
=> x = 3 * 7 / 2
=> x = 21/2
-=> x= 10.5
the corresponding median of the other triangle is 10.5 cm
Learn More:
perimeters of two similar triangles are 30cm and 40cm respectively ...
brainly.in/question/18128501
Ratio of area of 2 similar triangles are 2:3. Area of the larger triangle is
brainly.in/question/7877543