Question

The perimeters of two squares are 40 and 96 metres respectively. Find the perimeter of another
square equal in area to the sum of the first two squares.

Answer 1

Perimeter of 1st square=40
Side of 1st square= 40/4
= 10
Are of 1st square= 10*10=100

Perimeter of 2nd square=96
Side of 2nd square=96/4 = 24
Area of 2nd square= 24*24 =576

Area of 3rd square= Sum of area of 1st 2 squares
=100+576
=676
Side of 3rd square = root 676
= 26
Perimeter of 3rd square= 26*4
= 104