the perimeters of two squares are 60 m and 144m respectively find the perimeter of another square equal in area to the sum of the first 2 squares
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answer is 288 plus 120 equals to 108
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Perimeter of square=4*side
Side of square 1 =60÷4= 15m
Side of square 2 =144÷4=36m
Area of a square = side*side
Area of square 1 =15*15=225msq
Area of square 2 =36*36=1296msq
Area of the new square= 225+1296
= 1521msq
Side of the new square = square root of 1521= 39m
Perimeter of new square = 39*4=156m
Side of square 1 =60÷4= 15m
Side of square 2 =144÷4=36m
Area of a square = side*side
Area of square 1 =15*15=225msq
Area of square 2 =36*36=1296msq
Area of the new square= 225+1296
= 1521msq
Side of the new square = square root of 1521= 39m
Perimeter of new square = 39*4=156m
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