Question

The perimeters of two squares are 848 cm and 436 cm. Find the perimeter of a square
whose area is equal to the sum of the areas of two squares,​

Answer 1

Answer:

Answer

Let the side of the first square be x cm and the side of the second square be y cm.

Given:-

[tex][/tex]

Perimeter of first square = 848 cm

We know that,

Perimeter of a square = 4 × side

⟹ 848 = 4 × x

⟹ 848/4 = x

⟹ 212 cm = x

Also given that,

Perimeter of second square = 436 cm.

⟹ 436 = 4 × y

⟹ 436/4 = y

⟹ 109 cm = y

And ;

Area of a square = Area of the first square + Area of the second square.

We know,

Area of a square = (side)²

So,

According to the above condition;

⟹ Area of the square = x² + y²

⟹ Area of the square = (212)² + (109)²

⟹ Area of the square = 44944 + 11881

⟹ Area of the square = 56825

⟹ (side)² = 56825

⟹ side = √56825

⟹ side = 238.37 cm

Now,

Perimeter of the square = 4 × side

Perimeter of the square = 4(238.37)

Perimeter of the square = 953.48 cm

∴ The perimeter of the required square is 953.48 cm.

Step-by-step explanation:

Hope it helps!!