Question

The period of a satellite in circcular orbit of radius 12000 km around a planet is 3h. What is the period o a satellite in circular orbit of radius 48000 km around the same planet ?

Answer 1

Answer:

Escape velocity =

2gR

Speed of satellite=

4

2gR

By force balance,

x

2

GMm

=

x

m(

4

2gR

)

2

x=

2gR

GM

×16=8

gR

GM

=8R

Height of satellite above earth's surface is 8R−R=7R