Question

The period of oscillation of a 31
simple pendulum is given by
\displaystyle T=2\pi
\sqrt{\frac{1}{g}}where l is
about 100 cm and is known to
1mm accuracy. The period is
about 2s. The time of 100
oscillations is measured by a
stop watch of least count 0.1 s.
The percentage error in g is​

Answer 1

Answer:

15%. Please mark me as brainliest