The permanent dipole moment of a molecule of water is
19 x 10^-18 escu-cm.What is the direction of this moment and magnitude in Cm?
Answers
Answered by
1
Explanation:
Dipole moment of each molecules =10
−30
c.
As 1 mole of the substance contains 6×10
23
molecules
Total dipole moment of all the molecules
p=6×10
23
×10
−30
Cm=6×10
−7
Cm
Initial potential energy U
i
=−pEcosθ=−6×10
−7
×10
7
cos0
o
=−6J
Final potential energy U
f
=−6×10
−6
×10
6
×cos60
o
=−3J
Work done =− (Change in potential energy)
=−[(−3)−(−6)]=−3J
Similar questions