Question

The permanent dipole moment of a molecule of water is
19 x 10^-18 escu-cm.What is the direction of this moment and magnitude in Cm?​

Answer 1

Explanation:

Dipole moment of each molecules =10

−30

c.

As 1 mole of the substance contains 6×10

23

molecules

Total dipole moment of all the molecules

p=6×10

23

×10

−30

Cm=6×10

−7

Cm

Initial potential energy U

i

=−pEcosθ=−6×10

−7

×10

7

cos0

o

=−6J

Final potential energy U

f

=−6×10

−6

×10

6

×cos60

o

=−3J

Work done =− (Change in potential energy)

=−[(−3)−(−6)]=−3J