The permutations and combinations of abcd taken 3 at a time are respectively
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31
Answer
Permutation 24
Combination 4
Explanation
The number of permutation is basically the number of choices of 3 elements of the set where the order is important.
The number of permutations of n object taken k at a time written as P(n, k)
is equal to n! / ( n - k )!
= 4! / ( 4 - 3)!
= 4! / 1!
= 4! = 4 x 3 x 2 x 1
= 24
The number of combinations is the number of choices of 3 elements of the set where order is not important
Formula for number of combinations of n, taken r at a time is
C(n, r) = n! / (n - r)! r!
here n is 4, and r is 3
=4! / (4 - 3)! 3!
=4! / 1! x 3!
=4! / 3!
=(4 x 3 x 2 x 1) / (3 x 2 x 1)
=4
Answered by
3
Answer:
24,4
Step-by-step explanation:
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