Question

the perpendicular bisector of line segment joining A(1,5) andB(4,6) cut the y-axis at point

Answer 1

Slope of the line joining the points = (6-5)/(4-1)
= 1/3
Therefore, slope of perpendicular bisector = -3
(You can check by using the formula m1m2 =-1 for perpendicular lines)

The perpendicular bisector will pass through the midpoint of the above line.
Midpoint = (5/2,11/2)

From the above point and slope found,
y-y1= m(x-x1)
Substituting the values, we get the line,
3x+y=13
For y-intercept, putting x=0,
y=13.

The point at which it cuts y-axis = (0,13)

Answer 2

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

We know that the points which lie on the perpendicular bisector are equidistant from these two points.

So, please take a look at the following attachment.

Hence the point on y axis is p(0,13)