Question

plse solve this ques its urgent plse

Answer 1

In figure 1.
AB=8 CM
CD=6 CM
AP=PB=4CM
CQ=QD=3CM
RADIUS=5CM
$by \: pythogoras \: theorem \\ in \: triangle \: ocq \\ oq {}^{2} + cq {}^{2} = oc {}^{2} \\ {x}^{2} + {3}^{2} = {5}^{2} \\ {x}^{2} = 25 - 9 \\ {x}^{2} = 16 \\ x = 4cm$
in triangle AOB
by pythogoras theorem
${op}^{2} + {ap}^{2} = {oa}^{2} \\ y {}^{2} + {4}^{2} = {5}^{2} \\ y = 3cm$
PQ=3+4=7cm
In figure 2.
in triangle OAP
by pythogoras theorem
$ap {}^{2} + {op}^{2} = {oa}^{2} \\ {4}^{2} + {op}^{2} = {5}^{2} \\ op {}^{2} = 25 - 16 = 9 \\ op = 3cm$
in triangle OCQ
by pythogoras theorem
${cq}^{2} + {oq}^{2} = {oc}^{2} \\ {3}^{2} + {oq}^{2} = 5 {}^{2} \\ oq {}^{2} = 25 - 9 \\ oq = 4cm$
Length of PQ=4-3=1cm