Question

the perpendicular bisector of line segment joining the points A 1,5 and B 4,6 cuts the y axis at

Answer 1

Perpendicular bisector = Cuts at mid point, and is perpendicular 

First find the mid point 
x coordinate = 1+4 / 2 = 2.5 
y coordinate = 5+6 / 2 = 5.5 
Mid point = (2.5, 5.5) 

Then find the slope of the bisector : 
Slope of the given line = (5-6) / (1-4) = 1/3 
Slope of given line multiplied by slope of bisector = -1 
Slope of bisector = -1 / (1/3) 
= -3 

Use the point slope form to find the bisector's formula : 
-3 = (5.5 - y) / (2.5 - x) 
-7.5 + 3x = 5.5 - y 
3x + y - 13 = 0 

Transform the formula into slope-intercept form 

3x + y - 13 = 0 
y = -3x + 13 

Because slope-intercept form is y = mx + c, where m is the slope and c is the y-intercept 

Therefore the perpendicular bisector cuts the y-axis at (0,13) 

Answer 2

Step-by-step explanation:

so the answer will be (0,13)

go through the steps and u will understand

hope this helps u

cheers :)