the perpendicular bisector of the line segment joining the points A(2,5)and B(3,8) cuts y axis at
Answers
Answer:
I think that answer will be 13
Given : the perpendicular bisector of the line segment joining the points A(2,5)and B(3,8) cuts y axis
To Find : coordinate of intersection point
Solution:
A(2,5)and B(3,8)
Slope = ( 8 - 5)/(3 - 2) = 3
Slope of perpendicular bisector = - 1/3
Mid point of A(2,5)and B(3,8)
= (2 + 3)/2 , ( 5 + 8)/2
= 5/2 , 13/2
Line with slope -1/3 and passing through ( 5/2 , 13/2)
y - 13/2 = (-1/3)(x - 5/2)
=> y = -x/3 + 5/6 + 13/2
=> y = -x/3 + 44/6
=> y = -x/3 + 22/3
Hence y intercept is ( 0 , 22/3)
Another method:
Point cutting at y axis - P (0 , y)
PA = PB => PA² = PB²
(0 - 2)² + (y - 5)² = (0 - 3)² + (y - 8)²
=> 4 + y² - 10y + 25 = 9 + y² - 16y + 64
=> 6y = 44
=> y = 44/6
=> y = 22/3
P (0 , y) = ( 0 , 22/3)
Learn More:
change the equation 2x+3y=6 into intercept form and explain in the ...
brainly.in/question/19264716
Show that the equation of the line having slope m and making x ...
brainly.in/question/13903485
