The perpendicular distance between 2x+6y +7= 0
& 2x+6y + 5 =0 is
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2x + 3y + 6 = 0 . . . . . (1) and
4x + 6y + 24 = 0 . . . . . (2) with slope - 4/6 = -2/3
The slope of the line orthogonal to the two lines is +3/2 and the equation of this line through the origin is given by
y = (3/2)x . . . . . (3) and the points of intersection of this line with (1) and (2) are given by
(-12/13, -18/13) and (-24/13, -36/13)
and the distance between (i.e. the distance between the parallel lines) is given by
D = (1/13)*sqrt[12^2 + 18^2) = sqrt(468)/13 = 1.6641
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