Question

The perpendicular distance from origin to the line having intercepts (4,-3) is

Answer 1

Answer:Question 18 If p is the length of perpendicular from the origin to the line whose intercepts on the axes are a and b, then show that 1/p^2 = 1/a^2 + 1/b^2.

Answer 2

Answer:

The perpendicular distance is 2.4 units.

Step-by-step explanation:

Given: intercepts of line as (4,-3).

To find the perpendicular distance from origin to the line.

We know that equation of line with x- intercept a & y-intercept b is given by:

(x/a)+(y/b)=1

So, the equation of line here is:

(x/4)+(y/-3)=1

    -3x+4y = - 12

Now we need to find distance of origin from this line.

And distance of point (x1,y1) from line ax+by+c=0 is given by:

d= $|\frac{ax_{1} +by_{1} +c}{\sqrt{a^{2}+b^{2} } } |$

 = $\frac{0+0+12}{\sqrt{9+16} }$

= $\frac{12}{5}$

$=2.4$ units.

So, the perpendicular distance from origin to the line having intercepts (4,-3) is 2.4 units.

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