The perpendicular distance from the origin
to the radical axis of the circles 2x2+2y2-
3x-y+3=0 and 3x² + 3y2 - x + y - 1 = 0 is
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2x2 + 2y? Si: -Зх — у 33 D Зх у + 3 %3 0
S2 : 3x? + 3y2 – x+y-1=0
So, equation of radial axis is
Si – S2 = 0
(-9x - 3y + 9) - (-2x + 2y - 2) = 0
-7x – 5y + 11 = 0
= 7x + 5y – 11 = 0
Perpendicular distance from P (0,0) to
7x + 5y – 11 = 0 is
d =√74
11√74
Hope you find this helpful.......
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