Question

The perpendicular distance of a 5 2 from the y axis

Answer 1

Answer:

2 units

Step-by-step explanation:

Let P(x, y) be the point on y axis which is perpendicular to Q(5,2).

Since the point P is on y axis, y=0 and since point P is perpendicular to point Q, x=5.

PQ=

$\sqrt{(x2 - x1) { }^{2} + (y2 - y1) {}^{2}}$

PQ=

$\sqrt{(5 - 5 ){}^{2} + (0 - 2) {}^{2} }$

PQ=

$\sqrt{( - 2) {}^{2} }$

Therefore, PQ=2 units.

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