The perpendicular from the origin to a line meets it at the point (-2, 9), find the equation of the line.
Answers
Answered by
36
hey mate
here is your answer
the slope of the line perpendicular line =y2-y1/x2-x1
=>9-0/-2-0
=>-9/2
the condition of the the perpendicularity
is that the slope of the lines would be -ve reciprocal.
thus
m=-1/-9/2
=2/9
where m is the slope of the line
thus ,by one point slope form
the equation is given by
=>y-y1=m(x-x1)
=>y-9=2/9(x+2)
=>9(y-9)=2(x+2)
=>9y-81=2x+4
=>9y=2x+85 is the equation.
# be brainly
here is your answer
the slope of the line perpendicular line =y2-y1/x2-x1
=>9-0/-2-0
=>-9/2
the condition of the the perpendicularity
is that the slope of the lines would be -ve reciprocal.
thus
m=-1/-9/2
=2/9
where m is the slope of the line
thus ,by one point slope form
the equation is given by
=>y-y1=m(x-x1)
=>y-9=2/9(x+2)
=>9(y-9)=2(x+2)
=>9y-81=2x+4
=>9y=2x+85 is the equation.
# be brainly
Answered by
9
Answer:
2x-9y+85=0
Step-by-step explanation:
slope of OC =9-0/-2-0=-9/2
OC Perpendicular AB
slope of AB=2/9
equation of line AB is
y-9=2/9(x+2)
9y-81=2x+4
2x-9y+85=0
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