the perpendicular op and oq drawn from the point o to ab and ac respectively, if are congruent. prove that ai is the bisector of cab
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Let us take Right triangle APO, right-angled at P,
OP is perpendicular to AB or APO = 90 °
Now,
In triangle ΔAQO, right-angled at Q,
QO is perpendicular to AC or AQO = 90 °
Taking both triangles ΔAPO and ΔAQO,
AO = AO (Common Side)
APO = AQO = 90 °
AQ = AP (Perpendicular being drawn from same point O)
Hence, by SAS (Side-Angle-Side Congruence Condition)
ΔAPO ≅ ΔAQO,
So, QAO = BAO (Corresponding Parts of Congruent triangles )
Or we can conclude that AO is the bisector of \angle QAP,
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