The pH of 0.1M solution of cyanic acid (HCNO) is 2.34. Calculate the ionization constant of the acid and its degree of ionization in the solution.
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Answer for the same is as follows PH = 2.34
PH = -LOG [H+]
[H+] = Antilog[-2.34] = 4.57 x 10-3
For,
Weak acid [H+] = ca = 4.57 x 10-3
c = 0.1 M
a = 4.57 x 10-3/0.1 = 0.0457
Ka = a2/c = (0.0457)2/0.1 = 2.09 x 10-4
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