Question

The pH of a 0.2 molar solution
of the acid HQ is 3. The value of the ionization constant Ka of this acid is:

​

Answer 1

Answer:

[H+] = 10^-3

[H+] = √Ka ×C

10^-6 = Ka × C

Ka = 10^-6/o.2

Ka = 0.5 × 10^-5

Ka = 5 × 10^-6

Thanks for Reading