Question

The ph of solution obtained by mixing 500ml of 0.15m h2so4 with 0.1m naoh is

Answer 1

Answer:

M1OHH2O⇌M1++OH−

0.4−x         x              x

Kb1=0.4−xx2

since x is small

Kb1=0.4x2

x2=0.4Kb1

x2=4×10−8

x=2×10−4

[OH−]=2×10−4

N2OHH2O⇌N2++OH−

30.8−y        y           y

Kb2=