The ph of the solution containing 10 ml of 0.1 and 10 ml of 0.05 m h2s o4 would be
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NaOH volume = 100ml or 0.1L Normality =0.1 N molarity= normality= 0.1M moles of NaOH = 0.1 × 0.1 = 0.01mol [using formula mole = C
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Explanation:
the solution containing 10 ml of 0.1 and 10 ml of 0.05 M H2 s o4
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