Question

the ph of the solution containing 10 ml of a 0.1N naoh & 10 ml of 0.05 N h2so4 would be

Answer 1

Well the solution will go like this.
Before neutralization.
Millimoles of HCl =50x0.4=20
Millimoles of NaOH= 50x0.2=10
After neutralization,
Millimoles of NaOH=0
Millimoles of HCl=10 (by the concept of limiting reagent)
HCl will get dissociated into H+ and Cl-
Now concentration of H+ = 10/100=0.1M (the solution becomes 100 ml)
SO by the formula
pH=-log[H+]
we will get pH= 1

Answer 2

Hello there!

Solution has been attached.

Hope it helps.