The phase difference between displacement and acceleration of a particle SHM is ............
(A)π/2rad (B)πrad
(C)2πrad (D)3π/2rad
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2
Answer:
pi (π) radian. or 180 degree
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Explanation:
Displacement in SHM is given by x = A sin( wt) where A is amplitude, w is angular velocity, t is instantaneous time.
Velocity is rate of change of displacement with time. Differentiating displacement with respect to time, we have,
V = Aw cos(wt)
Phase difference between sin and cos function is 90 degrees or pi/2 radians . Hence phase difference between displacement and velocity is 90 degrees or pi/2 radians.
Similarly, acceleration can be obtained by differentiating equation of velocity.
Acceleration a = - Aw^2 sin (wt)
Hence phase difference between velocity and acceleration is also pi/2.
hope it will helps u
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