Physics, asked by ItsZisha7, 11 months ago

The phase difference between displacement and acceleration of a particle SHM is ............
(A)π/2rad (B)πrad
(C)2πrad (D)3π/2rad​

Answers

Answered by Ritam21
2

Answer:

pi (π) radian. or 180 degree

Answered by Anonymous
3

Explanation:

Displacement in SHM is given by x = A sin( wt) where A is amplitude, w is angular velocity, t is instantaneous time.

Velocity is rate of change of displacement with time. Differentiating displacement with respect to time, we have,

V = Aw cos(wt)

Phase difference between sin and cos function is 90 degrees or pi/2 radians . Hence phase difference between displacement and velocity is 90 degrees or pi/2 radians.

Similarly, acceleration can be obtained by differentiating equation of velocity.

Acceleration a = - Aw^2 sin (wt)

Hence phase difference between velocity and acceleration is also pi/2.

hope it will helps u

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