Question

The phase difference between two points distant 11m apart is 1320°. The frequency of the wave is 105Hz. The
velocity is
1)315m/s 2) 4235m/s
3) 1155m/s
4)380m/s​

Answer 1

Answer:

1) 315m/s

Explanation:

$t = \frac{1}{f} = \frac{1}{105} sec \\ t \: is \: for \: one complete \: rotation \: of \: 360 \\ t = t \times 1320 \div 360 \\ v = \ \frac{11}{t} = \frac{11 \times 360}{t \times 1320} = \frac{11 \times 360 \times 105}{1320} \\ v = 315msec {?}^{2} \:$