Physics, asked by dschouhan8603, 1 year ago

the phase difference between two points separated by 1m in a wave of frequency 120hz is 90° the wave velocity is

Answers

Answered by luk3004
4

480 m/s is the answer

Answered by Mahinsadaf
12

path difference = lamda fai /2

\pi

1=lamda/2 pi ×2 pi

1=lamda/4

lamda =4m

hence v=n×lamda

=120×4=480m/sec

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