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The photoelectric cut off voltage in a circuit experiment is 1.5 volt the maximum kinetic energy of emitted

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Answered by Anonymous
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The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted? Therefore, the maximum kinetic energy of the photoelectrons emitted in the given experiment is 2.4 × 10−19 J.

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