The photoelectric threshold wavelength of silver is
Answers
Answered by
0
The threshold wavelength for thephotoelectric effect for silver is 262 nm.
Answered by
8
Hey dear,
● Complete question is -
The photoelectric threshold wavelength of silver is 3250 x 10^-10 m. The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength 2536x10^-10 m is -
● Answer -
v = 3×10^5 m/s
● Explaination -
Energy of electron -
hυ = hc/λ
hυ = 6.6×10^-34 × 3×10^8 / (2536×10^-10)
hυ = 7.8×10^-19 J
Threshold energy -
hυ0 = hc/λ0
hυ0 = 6.6×10^-34 × 3×10^8 / (3250×10^-10)
hυ = 6.1×10^-19 J
Kinetic energy is -
1/2 mv^2 = hυ - hυ0
1/2 × 9.1×10^-31 × v^2 = 7.8×10^-19 - 6.1×10^-19
v = 3×10^5 m/s
Therefore, velocity of the ejected electron is 3×10^5 m/s.
Hope this helps you...
● Complete question is -
The photoelectric threshold wavelength of silver is 3250 x 10^-10 m. The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength 2536x10^-10 m is -
● Answer -
v = 3×10^5 m/s
● Explaination -
Energy of electron -
hυ = hc/λ
hυ = 6.6×10^-34 × 3×10^8 / (2536×10^-10)
hυ = 7.8×10^-19 J
Threshold energy -
hυ0 = hc/λ0
hυ0 = 6.6×10^-34 × 3×10^8 / (3250×10^-10)
hυ = 6.1×10^-19 J
Kinetic energy is -
1/2 mv^2 = hυ - hυ0
1/2 × 9.1×10^-31 × v^2 = 7.8×10^-19 - 6.1×10^-19
v = 3×10^5 m/s
Therefore, velocity of the ejected electron is 3×10^5 m/s.
Hope this helps you...
Similar questions