Question

The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0 m. If the piston moves with simple harmonic motion with an angular frequency of 200 rad/min, what is its maximum speed?​

Answer 1

$\huge \mathcal{SOLUTION}$

Angular frequency of the piston, ω = 200 rad/ min.

Stroke = 1.0 m

Amplitude, A = 1.0/2 = 0.5 m

The maximum speed (vmax) of piston is given by the relation:

vmax = Aω = 200 × 0.5 = 100m/min.

Answer 2

Answer:

1.67m/sec

Explanation:

Angular frequency of the piston, ω = 200 rad/ min.

Stroke = 1.0 m

Amplitude, A = 1.0/2 = 0.5 m

The maximum speed (Vmax) of piston is given by the relation:

Vmax = Aω = 200 × 0.5 = 100m/min.

Hence Vmax= 1.67 m/sec.