Question

The pitch and the number of divisions, on the circular scale, for a given screw gauge are 0.5 mm and 100 respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line. The readings of the main scale and the circular scale for a thin sheet, are 5.5 mm and 48 respectively, the thickness of this sheet is
(A) 5.755 mm (B) 5.950 mm
(C) 5.725 mm (D) 5.740 mm

Answer 1

Answer:

b

Explanation:

Answer 2

Thus the readings of the main scale and the circular scale for a thin sheet, are 5.5 mm and 48 respectively, the thickness of this sheet is 5.725 mm

Explanation:

LC =   Pitch  / No. of division

LC = 0.5 x 10^-2 mm

+ve error = 3 x 0.5 x 10^-2 mm

LC = 1.5 x 10^-2 mm = 0.015 mm

Reading = MSR + CSR - (+ve error)

Reading =  5.5 mm +(48 x 0.5 x 10^-2) - 0.015

Reading =  5.5 + 0.24 - 0.015 = 5.725 mm

Thus the readings of the main scale and the circular scale for a thin sheet, are 5.5 mm and 48 respectively, the thickness of this sheet is 5.725 mm