Question

The plates of a condenser are given charge of 10 micro
coulombs. If the potential difference across the plates is 200
volts, calculate the capacitance.​

Answer 1

Answer:

Correct option is

D

60V

Charge acquired by the plates of the capacitor q0=CV=(10μF)×(50V)=500μC

Now, let the charge distribution is as follows.

Total charge on positive plate has now become 700μC while that in negative plate is still −500μC.

Here, charges are in μC.

Net electric field at point P is zero.

∴2Aε0(700−q)+2Aε0q+(2Aε0500−q)=2Aε0q

⇒q=600μC

∴ Potential difference between the plates is

ΔV=Cq=10μF600μC=60V