Question

the pOH of solution os 4. the [H+] ion concentration solution is?​

Answer 1

Given -

=>  pOH of solution is 4.

To find -

[H+] ion concentration of the solution in molar (M) .

Concepts/Formulae Used Here -

    1) pOH + pH = 14

• Sum of pH and pOH for EVERY SOLUTION is always equal to 14.

   2) pH = -log₁₀[H+ ]

• The pH of a solution is given by the negative log of the [H+] ion concentration in molars (M).

Solving for pH -

We use the relation -

» pOH + pH = 14

=>  4 + pH = 14

=>  pH = 14-4

=> pH = 10

» Thus, the pH of the solution is 10 .

Solving for the [H+] ion concentration -

We use the relation -

» pH = -log₁₀[H+ ]

=>  10 = -log₁₀[H+] (Transposing -1 to L.H.S)

=>  10/-1 = log₁₀[H+]

=> -10 = log₁₀[H+]

=> log₁₀[H+] = -10

∵ If, logₐb = c then, aᶜ = b

∴  10⁻¹⁰ = [H+]

=> [H+] = 10⁻¹⁰ M (molar)

Answer -

=> The concentration of H+ ions in the solution is 10⁻¹⁰ M (molar) .

More to know -

• This solution is alkaline in nature as the [H+] ion concentration in molar is less than 10⁻⁷  M and pH is greater than 7 .

• If the [H+] ion concentration is more than 10⁻⁷ M, then the solution will be acidic .

• In pure water, the molar concentration of H+ is 10⁻⁷ M and that of OH- is also 10⁻⁷ M, the product of this is 10⁻¹⁴ M .

• In all solutions, the product of molar concentrations of [H+] and [OH-] is always 10⁻¹⁴ M (molar) .

        $[H]^{+} \times{[OH]^{-} } = 10^{-14}$