Question

The point A (3,y) is equidistant from the points P (6,5) and Q (0,-3). Find yhe value of y

Answer 1

I can use the distance formula so you get the answer

Answer 2

Answer:

The value of y is 1

Step-by-step explanation:

Given point A(3,y) is equidistant from the points P(6,5) and Q(0,-3).

we have to find the value of y.

By distance formula,

Distance between the coordinates $(x_1,y_1)\text{ and }(x_2,y_2)$ is

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

As, AP=AQ

$\sqrt{(6-3)^2+(5-y)^2}=\sqrt{(0-3)^2+(-3-y)^2}\\\\\text{Squaring on both sides}\\\\9+25+y^2-10y=9+9+y^2+6y\\\\34+y^2-10y=18+y^2+6y\\\\16-16y=0\\\\y=1$