The point (a, a) always lies on the line
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the point a will always lie on the line,
y-a = m(x-a)
where m is the slope of the line
y-a = m(x-a)
where m is the slope of the line
hardyk09:
i took the general equation --- y-y1=m(x-x1)
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The point (a, a) always lies on the line :
The point is (a,a)
taking the equ. x+y=0
putting x=a, y=a
=> L.H.S x+y=a+a=2a=R.H.S
so point (a, a) lies on the equ. x+y=2a
The point is (a,a)
taking the equ. x+y=0
putting x=a, y=a
=> L.H.S x+y=a+a=2a=R.H.S
so point (a, a) lies on the equ. x+y=2a
HOW CAN YOU TAKE THE EQUATION X+Y=0
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