Question

the point of interesting of the parabola y²=4x and the straight line x=4 are​

Answer 1

Step-by-step explanation:

Intersection of y²=4x and x = 4

So intersection point will satisfy both the equations...

y²=4x

put x = 4

y²=16

[y = +/- 4]

(4,4) & (4,-4)

Answer 2

Answer:

Put x = 4 in question of parabola . we get

${y}^{2} = 4x = 4 \times 4 \\ {y}^{2} = 16 \\ y = \pm4$

So we get two intersection points . those are

( 4 , 4 ) & ( 4 , -4 )