the point on the line 2x -3y -5 =0 which is equidistant from (1,2) and (3,4) is
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x = (x₁ + x₂)/2 y = y₁ + y₂/ 2
= 1 + 3 / 2 = 2 + 4 / 2
= 4 / 2 = 6 / 2
x = 2 y = 3
Therefore the coordinates of the point are (2,3).
= 1 + 3 / 2 = 2 + 4 / 2
= 4 / 2 = 6 / 2
x = 2 y = 3
Therefore the coordinates of the point are (2,3).
Answered by
2
Answer:
The coordinates of the point are (2,3).
Step-by-step explanation:
x = (x₁ + x₂)/2 y = y₁ + y₂/ 2
= 1 + 3 / 2 = 2 + 4 / 2
= 4 / 2 = 6 / 2
x = 2 y = 3
Therefore the coordinates of the point are (2,3).
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