Math, asked by Honey261, 1 year ago

the point on the line 2x -3y -5 =0 which is equidistant from (1,2) and (3,4) is

Answers

Answered by manohari
8
x = (x₁ + x₂)/2           y = y₁ + y₂/ 2
   = 1 + 3 / 2                 = 2 + 4 / 2
   = 4 / 2                       = 6 / 2
 x  = 2                           y = 3
Therefore the coordinates of the point are (2,3).
Answered by anubhav7268
2

Answer:

The coordinates of the point are (2,3).

Step-by-step explanation:

x = (x₁ + x₂)/2           y = y₁ + y₂/ 2

   = 1 + 3 / 2                 = 2 + 4 / 2

   = 4 / 2                       = 6 / 2

 x  = 2                           y = 3

Therefore the coordinates of the point are (2,3).

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