Question

The point on the x-axis which is equidistant from (-6, 0) and (10,0) is ?​

Answer 1

Step-by-step explanation:

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Answer 2

The point on the x - axis which is equidistant from (-6, 0) and (10, 0) is ..

solution : let the point on the x - axis is (x , 0)

now distance between (x, 0) and (-6, 0) = √{(x + 6)² + (0 - 0)²} = |x + 6|

distance between (x , 0) and (10, 0) = √{(x - 10)² + (0 - 0)²} = |x - 10|

as (x , 0) is equidistant from (-6, 0) and (10, 0).

⇒|x + 6| = |x - 10|

⇒x + 6 = ±(x - 10)

⇒x + 6 = -(x - 10) [ as we see, x + 6 ≠ x - 10 because 6 ≠ -10]

⇒x + 6 = - x + 10

⇒2x = 4

⇒x = 2

Therefore the point on the x - axis is (2, 0)

⇒