The point represented by 2 + i in the Argand plane moves 1 unit eastwards, then 2 units northwards and finally from there 2√2 units in the south–westwards direction. Then its new position in the Argand plane is at the point represented by :
(a) 1 + i
(b) 2 + 2i
(c) –2 – 2i
(d) –1 – i
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Answer).
Solution :
Let P(2 + i)
By rotation theorem
z−(35i)3+i−(3+3i)=22–√2e(−z/4)i
z−3−3i−2i=1−i
z−3−3i=−2i−2
z=1+i.
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