the point size image of a tall building is produced at a distance 10 cm from a concave mirror. find the image distance if the object is placed at the distance of 15 cm from the mirror,
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1/f = 1/u+1/v
1/f - 1/u = 1/v
1/10-1/15 =1/v
15-10/10*15 = 1/v
5/150 = 1/v
1/30 = 1/v
v = +30cm
1/f - 1/u = 1/v
1/10-1/15 =1/v
15-10/10*15 = 1/v
5/150 = 1/v
1/30 = 1/v
v = +30cm
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