Question

the point which divides the line segment joining (-2,4),(2,7) in the ratio 2:1 externally is

Answer 1

Given:

The end points of a segment are (-2,4) and (2,7).

A point divide the segment is 2:1 externally.

To find:

The coordinates of that point.

Solution:

If a point divides a line segment in m:n externally, then

$Point=\left(\dfrac{mx_2-nx_1}{m-n},\dfrac{my_2-ny_1}{m-n}\right)$

Using this formula, we get

$Point=\left(\dfrac{2(2)-1(-2)}{2-1},\dfrac{2(7)-1(4)}{2-1}\right)$

$Point=\left(\dfrac{4+2}{1},\dfrac{14-4}{1}\right)$

$Point=(6,10)$

Therefore, the required point is (6,10).

Answer 2

Answer:

Given:

The end points of a segment are (-2,4) and (2,7).

A point divide the segment is 2:1 externally.

To find:

The coordinates of that point.

Solution:

If a point divides a line segment in m:n externally, then

Point=(\dfrac{mx_2-nx_1}{m-n},\dfrac{my_2-ny_1}{m-n})Point=(m−nmx2−nx1,m−nmy2−ny1)

Using this formula, we get

Point=(\dfrac{2(2)-1(-2)}{2-1},\dfrac{2(7)-1(4)}{2-1})Point=(2−12(2)−1(−2),2−12(7)−1(4))

Point=(\dfrac{4+2}{1},\dfrac{14-4}{1})Point=(14+2,114−4)

Point=(6,10)Point=(6,10)

Therefore, the required point is (6,10).

mark me as brainliest and thank my answers