Math, asked by SRISAI38171, 1 year ago

The point which divides the line segment joining (a+b,a-b),(a-b,a+b)in the ratio a:b externally is

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Answered by arjun7774
15
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Answered by Anonymous
30

AB=given points are A(a+b,a-b) and B(a-b,a+b)

ratio a:b externally

section formulae

A(x1,y1) B(x2,y2) C(x,y)

m:n externally

(x,y)=(mx2 - nx1)/(m-n) , (my2-ny1)/(m-n)

(x,y)=[a(a-b)-b(a+b)]/(m-n),[(a(a+b)-b(a-b))/(m-n)]

by solving,

(x,y)=(a²-2ab-b²)/(a-b) , (a²+b²)/(a-b)

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