the points (1,6) and (12,9) are the two opposite vertices of a parallelogram. the other two vertices lie on the line 3y=11 x+k. then k is
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Let (1,6) be one end of the diagonal [A]
Let (12,9) other end of the diagonal [B]
Mid-point of the diagonal AB =[(12+1)/2] , [(9+6)/2)]
=(13/2,15,2)
3(15/2) = 11(13/2) + k
45/2 = 143/2 + k
k = 45/2 - 143/2
k = -98/2 = -49
Let (12,9) other end of the diagonal [B]
Mid-point of the diagonal AB =[(12+1)/2] , [(9+6)/2)]
=(13/2,15,2)
3(15/2) = 11(13/2) + k
45/2 = 143/2 + k
k = 45/2 - 143/2
k = -98/2 = -49
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