Question

The points (7, 2) and (-1,0) lie on a line
a. 7y= 3x - 7
b. 4y = x +1
c. y = 7
+7
d.x=4y+1
​

Answer 1

Answer:

The points (7, 2) and (-1,0) lie on a line

b. 4y = x + 1

Step-by-step explanation:

Verify the equation given in the options by putting (7,2) and (-1,0) .

Hope it helps you..

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Answer 2

The points (7, 2) and (-1, 0) lie on the line  4y = x + 1

Solution:

Given that,

The points (7, 2) and (-1,0) lie on a line

If a point lies on a line, it satisfies the equation of that line.

Option A

7y = 3x - 7

Substitute x = 7 and y = 2 in above

7(2) = 3(7) - 7

14 = 21 - 7

14 = 14

Substitute x = -1 and y = 0

7(0) = 3(-1) - 7

7 = -3 - 7

$7 \neq -10$

Thus, points (7, 2) and (-1,0) does not lie on 7y = 3x - 7

Option B

4y = x + 1

Substitute x = 7 and y = 2 in above

4(2) = 7 + 1

8 = 8

Substitute x = -1 and y = 0

4(0) = -1 + 1

0 = 0

Thus, points (7, 2) and (-1,0) lie on 4y = x + 1

Option C

y = 7x + 7

Substitute x = 7 and y = 2 in above

2 = 7(7) + 7

2 = 49 + 7

$2\neq 56$

Substitute x = -1 and y = 0

0 = 7(-1) + 7

0 = 0

Thus, points (7, 2) and (-1,0) does not lie on y = 7x + 7

Option D

x = 4y + 1

Substitute x = 7 and y = 2 in above

7 = 4(2) + 1

$7\neq 9$

Substitute x = -1 and y = 0

$-1 = 4(0) + 1\\\\-1\neq 1$

Thus, points (7, 2) and (-1,0) does not lie on x = 4y + 1

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