the points a(4 -2) b(7 2) c(0 9) and d(-3 5) form a parallelogram. find the length of altitude of parallelogram on base ab
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The parallelogram will have to triangles of equal areas in it.
Area of triangle ABC =( 4 ( 2-9) + 7(9-(-2))) 1/2 = 49/2
AB = √(3^2 + 4^2) = 5
Area of triangle = 1/2 base * height = 1/2 * AB * altitude
49 = 5 * altitude
altitude = 9.8 units
Area of triangle ABC =( 4 ( 2-9) + 7(9-(-2))) 1/2 = 49/2
AB = √(3^2 + 4^2) = 5
Area of triangle = 1/2 base * height = 1/2 * AB * altitude
49 = 5 * altitude
altitude = 9.8 units
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