Question

The points A(5,0),B(5,-3),C(-4,-3) and D(-4,0) are the vertices of a
(a) square
(b) rectangle
(c)rhombus
(d)trapezium​

Answer 1

Step-by-step explanation:

So by distance formula,

Distance between two points =

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

AB=

(−5+3)

2

+(−5−2)

2

=

4+49

=

53

.

BC=

(2+5)

2

+(−3+5)

2

=

49+4

=

53

.

CD=

(4−2)

2

+(4+3)

2

=

4+49

=

53

.

DA=

(4+3)

2

+(4−2)

2

=

49+4

=

53

.

∴AB=BC=CD=AD

Hence, ABCD is a rhombus (Proved)

Area of the rhombus ABCD

Answer 2

Answer:

the answer is rectangle (option b).

Step-by-step explanation:

when u will plot the points, u will find that length is 9 units and breadth is 3 units

OR

in A and B points value of x is same i.e. 5

in A and D points value of y is same i.e. 0

in C and D points value of x is same i.e. -4

in C and B points value of y is same i.e. -3

this way we can see that all the lines are parallel to each other.

thank you