The points A B C are collinear having a b c tangent to it prove that a2BC+b2AC+c2AB=0
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Step-by-step explanation:
If points are collinear, then area=0
or(
2
1
)[a(d−b+d)−b(c−a+c)+1(cb−cd−ad+cd)]=0
a(2d−b)−b(2c−a)+(cd−ad)=0
2ad−ab−2bc+ab+cb−ad=0
ad−bc=0
orad=bc
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