Question

The points (K, 3), (2, -4) and (-K + 1,
-2) are collinear. Find K.​

Answer 1

Answer:

I think this helps u bro plz give like

Answer 2

$\huge\bold{\gray{\sf{Given:}}}$

Three points A(K,3),B(2,-4)&C(-k+1)

$\huge\bold{\gray{\sf{To \:Find:}}}$

The value of k..??

$\huge\bold{\gray{\sf{Answer:}}}$

Formula :

$\bold{\boxed{\frac{1}{2} [x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2] = 0}}$

Points A(K,3),B(2,-4)&C(-k,1)

Here ,X1=k,X2=2,X3=-k

Y1=3,Y2=-4 &Y3=1

$\bold{= > \frac{1}{2} [k( - 4 - 1) + 2(1 - 3) (+ ) - k(3 - ( - 4)]= 0}$

$\bold{= > \frac{1}{2} [k( - 5) + 2 ( - 2) - k(7)]= 0}$

$\bold{= > \frac{1}{2} ( - 5k - 4 - 7k) = 0}$

$\bold{= > \frac{1}{2} ( - 12k - 4) = 0}$

$\bold{= > - 12k - 4 = 0}$

$\bold{= > - 12k = 4}$

$\bold{= > k = \frac{4}{ - 12} = - \frac{1}{3} }$

Value of k is -1/3.